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1. This is a study on the utilization volume of the 94 native Korean red pines in Kwangyan Forests. 2. The formulas which derived by the above investigation are follows. a. Hight growth curve ; H = 4.76 + 0.125D ÷ 0.0026D b. Cubic volume form...
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부가정보
다국어 초록 (Multilingual Abstract)
1. This is a study on the utilization volume of the 94 native Korean red pines in Kwangyan Forests.
2. The formulas which derived by the above investigation are follows.
a. Hight growth curve ;
H = 4.76 + 0.125D ÷ 0.0026D
b. Cubic volume formula ;
V = 0.0000839D^(2.3) H^(0.2)
c. The relation between utilization volume and log length ;
Vu = 0.1708 - 0.0230L
d. The percentage of utilization, when length was 2 meters ;
P = 27.37 D^(0.3648)
e. The number of 2 meter long timbers ;
N = 0.0863D^(1.15)
f. The equation of the utilization timber volume when log length was 2 meters ;
Vu = 0.0000159D²H^(1.3)
3. As a conclusion, it was found that the utilization volume in the case of 2 meter lot, was most greater than the others.
2. The formulas which derived by the above investigation are follows.
a. Hight growth curve ;
H = 4.76 + 0.125D ÷ 0.0026D
b. Cubic volume formula ;
V = 0.0000839D^(2.3) H^(0.2)
c. The relation between utilization volume and log length ;
Vu = 0.1708 - 0.0230L
d. The percentage of utilization, when length was 2 meters ;
P = 27.37 D^(0.3648)
e. The number of 2 meter long timbers ;
N = 0.0863D^(1.15)
f. The equation of the utilization timber volume when log length was 2 meters ;
Vu = 0.0000159D²H^(1.3)
3. As a conclusion, it was found that the utilization volume in the case of 2 meter lot, was most greater than the others.
1. This is a study on the utilization volume of the 94 native Korean red pines in Kwangyan Forests.
2. The formulas which derived by the above investigation are follows.
a. Hight growth curve ;
H = 4.76 + 0.125D ÷ 0.0026D
b. Cubic volume formula ;
V = 0.0000839D^(2.3) H^(0.2)
c. The relation between utilization volume and log length ;
Vu = 0.1708 - 0.0230L
d. The percentage of utilization, when length was 2 meters ;
P = 27.37 D^(0.3648)
e. The number of 2 meter long timbers ;
N = 0.0863D^(1.15)
f. The equation of the utilization timber volume when log length was 2 meters ;
Vu = 0.0000159D²H^(1.3)
3. As a conclusion, it was found that the utilization volume in the case of 2 meter lot, was most greater than the others.
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